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To calculate edge length in terms of r the equation is as follows: An example of a Simple Cubic unit cell is Polonium. Thus, the statement there are eight next nearest neighbours of Na+ ion is incorrect. Silver crystallizes with a FCC; the raidus of the atom is 160 pm. Suppose if the radius of each sphere is r, then we can write it accordingly as follows. It shows the different properties of solids like density, consistency, and isotropy. In simple cubic structures, each unit cell has only one atom. Question 1: Packing efficiency of simple cubic unit cell is .. The steps below are used to achieve Body-centered Cubic Lattices Packing Efficiency of Metal Crystal. Concepts of crystalline and amorphous solids should be studied for short answer type questions. ", Qur, Yves. CsCl is more stable than NaCl, for it produces a more stable crystal and more energy is released. 200 gm is the mass =2 200 / 172.8 10, Calculate the void fraction for the structure formed by A and B atoms such that A form hexagonal closed packed structure and B occupies 2/3 of octahedral voids. The corners of the bcc unit cell are filled with particles, and one particle also sits in the cubes middle. Particles include atoms, molecules or ions. In triangle ABC, according to the Pythagoras theorem, we write it as: We substitute the values in the above equation, then we get. Like the BCC, the atoms don't touch the edge of the cube, but rather the atoms touch diagonal to each face. The whole lattice can be reproduced when the unit cell is duplicated in a three dimensional structure. In this, there are the same number of sites as circles. Try visualizing the 3D shapes so that you don't have a problem understanding them. Packing efficiency is the proportion of a given packings total volume that its particles occupy. Since chloride ions are present at the corners of the cube, therefore, we can determine the radius of chloride ions which will be equal to the length of the side of the cube, therefore, the length of the chloride will be 2.06 Armstrong and cesium ion will be the difference between 3.57 and 2.06 which will be equal to 1.51 Armstrong. Moment of Inertia of Continuous Bodies - Important Concepts and Tips for JEE, Spring Block Oscillations - Important Concepts and Tips for JEE, Uniform Pure Rolling - Important Concepts and Tips for JEE, Electrical Field of Charged Spherical Shell - Important Concepts and Tips for JEE, Position Vector and Displacement Vector - Important Concepts and Tips for JEE, Parallel and Mixed Grouping of Cells - Important Concepts and Tips for JEE, Find Best Teacher for Online Tuition on Vedantu. Therefore, the ratio of the radiuses will be 0.73 Armstrong. The packing efficiency is the fraction of space that is taken up by atoms. How can I solve the question of Solid States that appeared in the IIT JEE Chemistry exam, that is, to calculate the distance between neighboring ions of Cs and Cl and also calculate the radius ratio of two ions if the eight corners of the cubic crystal are occupied by Cl and the center of the crystal structure is occupied by Cs? The packing efficiency of the face centred cubic cell is 74 %. Touching would cause repulsion between the anion and cation. Question 5: What are the factors of packing efficiency? Thus, in the hexagonal lattice, every other column is shifted allowing the circles to nestle into the empty spaces. It must always be seen less than 100 percent as it is not possible to pack the spheres where atoms are usually spherical without having some empty space between them. space (void space) i.e. Unit Cells: A Three-Dimensional Graph . Additionally, it has a single atom in the middle of each face of the cubic lattice. The volume of the unit cell will be a3 or 2a3 that gives the result of 8a3. "Stable Structure of Halides. Give two other examples (none of which is shown above) of a Face-Centered Cubic Structure metal. Also, the edge b can be defined as follows in terms of radius r which is equal to: According to equation (1) and (2), we can write the following: There are a total of 4 spheres in a CCP structure unit cell, the total volume occupied by it will be following: And the total volume of a cube is the cube of its length of the edge (edge length)3. Body-centered Cubic (BCC) unit cells indicate where the lattice points appear not only at the corners but in the center of the unit cell as well. In this article, we shall study the packing efficiency of different types of unit cells. The calculation of packing efficiency can be done using geometry in 3 structures, which are: CCP and HCP structures Simple Cubic Lattice Structures Body-Centred Cubic Structures Factors Which Affects The Packing Efficiency Touching would cause repulsion between the anion and cation. The cubic closed packing is CCP, FCC is cubic structures entered for the face. A crystal lattice is made up of a relatively large number of unit cells, each of which contains one constituent particle at each lattice point. Below is an diagram of the face of a simple cubic unit cell. To determine its packing efficiency, we should be considering a cube having the edge length of a, the cube diagonal as c, and the face diagonal length as b. Therefore, if the Radius of each and every atom is r and the length of the cube edge is a, then we can find a relation between them as follows. (8 corners of a given atom x 1/8 of the given atom's unit cell) + (6 faces x 1/2 contribution) = 4 atoms). The reason for this is because the ions do not touch one another. Find molar mass of one particle (atoms or molecules) using formula, Find the length of the side of the unit cell. It shows various solid qualities, including isotropy, consistency, and density. Consistency, density, and isotropy are some of the effects. Packing Efficiency of Simple Cubic Having a co-relation with edge and radius of the cube, we take: Also, edge b of the cube in relation with r radius is equal to: In ccp structure of the unit cell, as there are four spheres, so the net volume is occupied by them, and which is given by: Further, cubes total volume is (edge length)3 that is a3 or if given in the form of radius r, it is given by (2 2 r)3, hence, the packing efficiency is given as: So, the packing efficiency in hcp and fcc structures is equal to 74%, Likewise in the HCP lattice, the relation between edge length of the unit cell a and the radius r is equal to, r = 2a, and the number of atoms = 6. Now, in triangle AFD, according to the theorem of Pythagoras. Question 3:Which of the following cubic unit cell has packing efficiency of 64%? Begin typing your search term above and press enter to search. For the sake of argument, we'll define the a axis as the vertical axis of our coordinate system, as shown in the figure . cubic closed structure, we should consider the unit cell, having the edge length of a and theres a diagonal face AC in below diagram which is b. Now correlating the radius and its edge of the cube, we continue with the following. Chemical, physical, and mechanical qualities, as well as a number of other attributes, are revealed by packing efficiency. Packing Efficiency is Mathematically represented as: Packing efficiency refers to spaces percentage which is the constituent particles occupies when packed within the lattice. In a simple cubic lattice, the atoms are located only on the corners of the cube. 6: Structures and Energetics of Metallic and Ionic solids, { "6.11A:_Structure_-_Rock_Salt_(NaCl)" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "6.11B:_Structure_-_Caesium_Chloride_(CsCl)" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "6.11C:_Structure_-_Fluorite_(CaF)" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "6.11D:_Structure_-_Antifluorite" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "6.11E:_Structure_-_Zinc_Blende_(ZnS)" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "6.11F:_Structure_-_-Cristobalite_(SiO)" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "6.11H:_Structure_-_Rutile_(TiO)" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "6.11I:_Structure_-_Layers_((CdI_2)_and_(CdCl_2))" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "6.11J:_Structure_-_Perovskite_((CaTiO_3))" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()" }, { "6.01:_Introduction" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "6.02:_Packing_of_Spheres" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "6.03:_The_Packing_of_Spheres_Model_Applied_to_the_Structures_of_Elements" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "6.04:_Polymorphism_in_Metals" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "6.05:_Metallic_Radii" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "6.06:_Melting_Points_and_Standard_Enthalpies_of_Atomization_of_Metals" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "6.07:_Alloys_and_Intermetallic_Compounds" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "6.08:_Bonding_in_Metals_and_Semicondoctors" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "6.09:_Semiconductors" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "6.10:_Size_of_Ions" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "6.11:_Ionic_Lattices" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "6.12:_Crystal_Structure_of_Semiconductors" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "6.13:_Lattice_Energy_-_Estimates_from_an_Electrostatic_Model" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "6.14:_Lattice_Energy_-_The_Born-Haber_Cycle" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "6.15:_Lattice_Energy_-_Calculated_vs._Experimental_Values" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "6.16:_Application_of_Lattice_Energies" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()", "6.17:_Defects_in_Solid_State_Lattices" : "property get [Map MindTouch.Deki.Logic.ExtensionProcessorQueryProvider+<>c__DisplayClass228_0.b__1]()" }, 6.11B: Structure - Caesium Chloride (CsCl), [ "article:topic", "showtoc:no", "license:ccbyncsa", "non-closed packed structure", "licenseversion:40" ], https://chem.libretexts.org/@app/auth/3/login?returnto=https%3A%2F%2Fchem.libretexts.org%2FBookshelves%2FInorganic_Chemistry%2FMap%253A_Inorganic_Chemistry_(Housecroft)%2F06%253A_Structures_and_Energetics_of_Metallic_and_Ionic_solids%2F6.11%253A_Ionic_Lattices%2F6.11B%253A_Structure_-_Caesium_Chloride_(CsCl), \( \newcommand{\vecs}[1]{\overset { \scriptstyle \rightharpoonup} {\mathbf{#1}}}\) \( \newcommand{\vecd}[1]{\overset{-\!-\!\rightharpoonup}{\vphantom{a}\smash{#1}}} \)\(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\) \(\newcommand{\id}{\mathrm{id}}\) \( \newcommand{\Span}{\mathrm{span}}\) \( \newcommand{\kernel}{\mathrm{null}\,}\) \( \newcommand{\range}{\mathrm{range}\,}\) \( \newcommand{\RealPart}{\mathrm{Re}}\) \( \newcommand{\ImaginaryPart}{\mathrm{Im}}\) \( \newcommand{\Argument}{\mathrm{Arg}}\) \( \newcommand{\norm}[1]{\| #1 \|}\) \( \newcommand{\inner}[2]{\langle #1, #2 \rangle}\) \( \newcommand{\Span}{\mathrm{span}}\)\(\newcommand{\AA}{\unicode[.8,0]{x212B}}\), tice which means the cubic unit cell has nodes only at its corners. Therefore body diagonalc = 4r, Volume of the unit cell = a3= (4r / 3)3= 64r3 / 33, Let r be the radius of sphere and a be the edge length of the cube, In fcc, the corner spheres are in touch with the face centred sphere. Here are some of the strategies that can help you deal with some of the most commonly asked questions of solid state that appear in IIT JEEexams: Go through the chapter, that is, solid states thoroughly. If the volume of this unit cell is 24 x 10. , calculate no. The atoms at the center of the cube are shared by no other cube and one cube contains only one atom, therefore, the number of atoms of B in a unit cell is equal to 1. Let us take a unit cell of edge length a. It is the entire area that each of these particles takes up in three dimensions. \[\frac{\frac{6\times 4}{3\pi r^3}}{(2r)^3}\times 100%=74.05%\]. Atoms touch one another along the face diagonals. In this article, we shall learn about packing efficiency. When we see the ABCD face of the cube, we see the triangle of ABC in it. They have two options for doing so: cubic close packing (CCP) and hexagonal close packing (HCP). It is a salt because it is formed by the reaction of an acid and a base. Substitution for r from equation 1, we get, Volume of one particle = 4/3 (3/4 a)3, Volume of one particle = 4/3 (3)3/64 a3. Where, r is the radius of atom and a is the length of unit cell edge. The ions are not touching one another. Crystallization refers the purification processes of molecular or structures;. Question 2:Which of the following crystal systems has minimum packing efficiency? Legal. Let a be the edge length of the unit cell and r be the radius of sphere. It doesnt matter in what manner particles are arranged in a lattice, so, theres always a little space left vacant inside which are also known as Voids. Example 1: Calculate the total volume of particles in the BCC lattice. These types of questions are often asked in IIT JEE to analyze the conceptual clarity of students. And so, the packing efficiency reduces time, usage of materials and the cost of generating the products. Its packing efficiency is the highest with a percentage of 74%. The packing efficiency is the fraction of crystal or known as the unit cell which is actually obtained by the atoms. What is the packing efficiency of diamond? By examining it thoroughly, you can see that in this packing, twice the number of 3-coordinate interstitial sites as compared to circles. Now we find the volume which equals the edge length to the third power. Thus, packing efficiency in FCC and HCP structures is calculated as 74.05%. For the most part this molecule is stable, but is not compatible with strong oxidizing agents and strong acids. Therefore, the value of packing efficiency of a simple unit cell is 52.4%. A-143, 9th Floor, Sovereign Corporate Tower, We use cookies to ensure you have the best browsing experience on our website. Therefore, in a simple cubic lattice, particles take up 52.36 % of space whereas void volume, or the remaining 47.64 %, is empty space. Packing efficiency of simple cubic unit cell is .. Each Cs+ is surrounded by 8 Cl- at the corners of its cube and each Cl- is also surrounded by 8 Cs+ at the corners of its cube. Your Mobile number and Email id will not be published. It can be evaluated with the help of geometry in three structures known as: There are many factors which are defined for affecting the packing efficiency of the unit cell: In this, both types of packing efficiency, hexagonal close packing or cubical lattice closed packing is done, and the packing efficiency is the same in both. Face-centered Cubic Unit Cell image adapted from the Wikimedia Commons file "Image: Image from Problem 3 adapted from the Wikimedia Commons file "Image: What is the edge length of the atom Polonium if its radius is 167 pm? Briefly explain your reasonings. The LibreTexts libraries arePowered by NICE CXone Expertand are supported by the Department of Education Open Textbook Pilot Project, the UC Davis Office of the Provost, the UC Davis Library, the California State University Affordable Learning Solutions Program, and Merlot. status page at https://status.libretexts.org, Carter, C. Lattice(BCC): In a body-centred cubic lattice, the eight atoms are located on the eight corners of the cube and one at the centre of the cube. The distance between the two atoms will be the sum of radium of both the atoms, which on calculation will be equal to 3.57 Armstrong. Knowing the density of the metal, we can calculate the mass of the atoms in the If the volume of this unit cell is 24 x 10-24cm3and density of the element is 7.20gm/cm3, calculate no. The packing efficiency of simple cubic lattice is 52.4%. By using our site, you So, 7.167 x 10-22 grams/9.265 x 10-23 cubic centimeters = 7.74 g/cm3. This misconception is easy to make, since there is a center atom in the unit cell, but CsCl is really a non-closed packed structure type. Which of the following is incorrect about NaCl structure? Packing Efficiency of Face CentredCubic We always observe some void spaces in the unit cell irrespective of the type of packing. Thus the radius of an atom is 3/4 times the side of the body-centred cubic unit cell. To packing efficiency, we multiply eight corners by one-eighth (for only one-eighth of the atom is part of each unit cell), giving us one atom. The percentage of packing efficiency of in cscl crystal lattice is a) 68% b) 74% c)52.31% d) 54.26% Advertisement Answer 6 people found it helpful sanyamrewar Answer: Answer is 68% Explanation: See attachment for explanation Find Chemistry textbook solutions? . Recall that the simple cubic lattice has large interstitial sites A crystal lattice is made up of a very large number of unit cells where every lattice point is occupied by one constituent particle. As with NaCl, the 1:1 stoichiometry means that the cell will look the same regardless of whether we start with anions or cations on the corner. It is a salt because it decreases the concentration of metallic ions. Because all three cell-edge lengths are the same in a cubic unit cell, it doesn't matter what orientation is used for the a, b, and c axes. The higher are the coordination numbers, the more are the bonds and the higher is the value of packing efficiency. Cesium chloride is used in centrifugation, a process that uses the centrifugal force to separate mixtures based on their molecular density. How may unit cells are present in a cube shaped ideal crystal of NaCl of mass 1.00 g? We provide you year-long structured coaching classes for CBSE and ICSE Board & JEE and NEET entrance exam preparation at affordable tuition fees, with an exclusive session for clearing doubts, ensuring that neither you nor the topics remain unattended. unit cell. We receieved your request, Stay Tuned as we are going to contact you within 1 Hour. CsCl is an ionic compound that can be prepared by the reaction: \[\ce{Cs2CO3 + 2HCl -> 2 CsCl + H2O + CO2}\]. Let us suppose the radius of each sphere ball is r. Anions and cations have similar sizes. It is an acid because it is formed by the reaction of a salt and an acid. Question 2: What role does packing efficiency play? Although it is not hazardous, one should not prolong their exposure to CsCl. It must always be less than 100% because it is impossible to pack spheres (atoms are usually spherical) without having some empty space between them. packing efficiencies are : simple cubic = 52.4% , Body centred cubic = 68% , Hexagonal close-packed = 74 % thus, hexagonal close packed lattice has the highest packing efficiency. Because the atoms are attracted to one another, there is a scope of squeezing out as much empty space as possible. How can I predict the formula of a compound in questions asked in the IIT JEE Chemistry exam from chapter solid state if it is formed by two elements A and B that crystallize in a cubic structure containing A atoms at the corner of the cube and B atoms at the body center of the cube? ions repel one another. 5. See Answer See Answer See Answer done loading Thus, the edge length or side of the cube 'a', and . Mathematically. . We approach this problem by first finding the mass of the unit cell. The CsCl structure is stable when the ratio of the smaller ion radius to larger ion radius is . In body-centered cubic structures, the three atoms are arranged diagonally. The lattice points in a cubic unit cell can be described in terms of a three-dimensional graph. In a simple cubic lattice structure, the atoms are located only on the corners of the cube. You'll get a detailed solution from a subject matter expert that helps you learn core concepts. Let 'a' be the edge length of the unit cell and r be the radius of sphere. way the constituent particles atoms, molecules or ions are packed, there is = 8r3. In 1850, Auguste Bravais proved that crystals could be split into fourteen unit cells. Substitution for r from r = 3/4 a, we get. Example 2: Calculate Packing Efficiency of Face-centered cubic lattice. There are two number of atoms in the BCC structure, then the volume of constituent spheres will be as following, Thus, packing efficiency = Volume obtained by 2 spheres 100 / Total volume of cell, = \[2\times \frac{\frac{\frac{4}{3}}{\pi r^3}}{\frac{4^3}{\sqrt{3}r}}\], Therefore, the value of APF = Natom Vatom / Vcrystal = 2 (4/3) r^3 / 4^3 / 3 r. Thus, the packing efficiency of the body-centered unit cell is around 68%. Therefore, the formula of the compound will be AB. The packing efficiency of simple cubic lattice is 52.4%. The percentage of the total space which is occupied by the particles in a certain packing is known as packing efficiency. Following are the factors which describe the packing efficiency of the unit cell: In both HCP and CCP Structures packing, the packing efficiency is just the same. Hence they are called closest packing. Example 4: Calculate the volume of spherical particles of the body-centered cubic lattice. Accessibility StatementFor more information contact us atinfo@libretexts.orgor check out our status page at https://status.libretexts.org. 8 Corners of a given atom x 1/8 of the given atom's unit cell = 1 atom To calculate edge length in terms of r the equation is as follows: 2r The cubes center particle hits two corner particles along its diagonal, as seen in the figure below. The steps below are used to achieve Face-centered Cubic Lattices Packing Efficiency of Metal Crystal: The corner particles are expected to touch the face ABCDs central particle, as indicated in the figure below. Diagram------------------>. Generally, numerical questions are asked from the solid states chapter wherein the student has to calculate the radius or number of vertices or edges in a 3D structure. Sodium (Na) is a metallic element soluble in water, where it is mostly counterbalanced by chloride (Cl) to form sodium chloride (NaCl), or common table salt. Though a simple unit cell of a cube consists of only 1 atom, and the volume of the unit cells containing only 1 atom will be as follows. We all know that the particles are arranged in different patterns in unit cells. In the NaCl structure, shown on the right, the green spheres are the Cl - ions and the gray spheres are the Na + ions. Solution Show Solution. Though each of it is touched by 4 numbers of circles, the interstitial sites are considered as 4 coordinates. ), Finally, we find the density by mass divided by volume. Thus, the percentage packing efficiency is 0.7854100%=78.54%. As per our knowledge, component particles including ion, molecule, or atom are arranged in unit cells having different patterns. Click on the unit cell above to view a movie of the unit cell rotating. The volume of the cubic unit cell = a3 = (2r)3 Mass of unit cell = Mass of each particle x Numberof particles in the unit cell, This was very helpful for me ! The void spaces between the atoms are the sites interstitial. Quantitative characteristic of solid state can be achieved with packing efficiencys help. There is one atom in CsCl. In the structure of diamond, C atom is present at all corners, all face centres and 50 % tetrahedral voids. The hcp and ccp structure are equally efficient; in terms of packing. Length of body diagonal, c can be calculated with help of Pythagoras theorem, \(\begin{array}{l} c^2~=~ a^2~ + ~b^2 \end{array} \), Where b is the length of face diagonal, thus b, From the figure, radius of the sphere, r = 1/4 length of body diagonal, c. In body centered cubic structures, each unit cell has two atoms. The metals such as iron and chromium come under the BSS category. Packing efficiency = volume occupied by 4 spheres/ total volume of unit cell 100 %, \[\frac{\frac{4\times 4}{3\pi r^3}}{(2\sqrt{2}r)^3}\times 100%\], \[\frac{\frac{16}{3\pi r^3}}{(2\sqrt{2}r)^3}\times 100%\]. Treat the atoms as "hard spheres" of given ionic radii given below, and assume the atoms touch along the edge of the unit cell. As sphere are touching each other. space not occupied by the constituent particles in the unit cell is called void It is usually represented by a percentage or volume fraction. Read the questions that appear in exams carefully and try answering them step-wise. Which has a higher packing efficiency? Number of atoms contributed in one unit cell= one atom from the eight corners+ one atom from the two face diagonals = 1+1 = 2 atoms, Mass of one unit cell = volume its density, 172.8 1024gm is the mass of one unit cell i.e., 2 atoms, 200 gm is the mass =2 200 / 172.8 1024atoms= 2.3148 1024atoms, _________________________________________________________, Calculate the void fraction for the structure formed by A and B atoms such that A form hexagonal closed packed structure and B occupies 2/3 of octahedral voids. Thus the radius of an atom is half the side of the simple cubic unit cell. Thus if we look beyond a single unit cell, we see that CsCl can be represented as two interpenetrating simple cubic lattices in which each atom . find value of edge lenth from density formula where a is the edge length, M is the mass of one atom, Z is the number of atoms per unit cell, No is the Avogadro number.

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